Pick the morph and both parents: the calculator gives the percentage of visual, het and normal offspring, for one or two genes at once.
| Parent 1 | Parent 2 | Visual babies | Normal babies that are het |
|---|---|---|---|
| Visual | Normal (not het) | 0% | 100% |
| Het (carrier) | Het (carrier) | 25% | 67% |
| Visual | Het (carrier) | 50% | 100% |
| Visual | Visual | 100% | — |
| 66% possible het | 66% possible het | 11.1% | 50% |
Inheritance from A. vulgare studies and crosses reported by breeders. If your results differ, tell me.
Two P. scaber het for Orange: 25% Orange babies, 75% normal-looking, of which 67% are het.
Sources: Hasegawa et al. (1997, Pigment Cell Research 10: 265), autosomal recessive albinism in Armadillidium vulgare; Howard (1962, Journal of Genetics 58: 29); breeder-reported crosses for P. scaber (Orange, Dalmatian: F1 all wild-type, F2 close to 9:3:3:1) and P. laevis (Smug Bug, Arachnoboards). Becking et al. (2017, Scientific Reports) for sex chromosomes and Wolbachia.
A normal-looking baby from two hets has a 2 in 3 chance of being het too. You can only tell by breeding it.
Not in the first generation: all babies look normal but are het. Breed them together (or back to the orange parent) to get oranges again.
Its inheritance is not established: it looks line-bred over several generations rather than caused by a single gene.
Write to me: I fix the numbers and improve the calculator.